12-04 03:23 阅读 217

VBA工程加密PJ方式(两种)

今天遇到一个excel小工具感觉不错，想研究研究代码，竟然有密码，我就不淡定了。网上找了找代码，改了一下就OK了。接下来通过本文给大家分享两种方式破解VBA工程加密，需要的朋友参考下吧

两种方式破解VBA加密代码

第一种：

Sub VBAPassword1() '你要解保护的Excel文件路径

    Filename = Application.GetOpenFilename("Excel文件（*.xls & *.xla & *.xlt）,*.xls;*.xla;*.xlt", , "VBA破解")

    If Dir(Filename) = "" Then

        MsgBox "没找到相关文件,清重新设置。"

        Exit Sub

    Else

        FileCopy Filename, Filename & ".bak" '备份文件。

    End If

    Dim GetData As String * 5

    Open Filename For Binary As #1

    Dim CMGs As Long

    Dim DPBo As Long

    For i = 1 To LOF(1)

        Get #1, i, GetData

        If GetData = "CMG=""" Then CMGs = i

        If GetData = "[Host" Then DPBo = i - 2: Exit For

    Next

    If CMGs = 0 Then

        MsgBox "请先对VBA编码设置一个保护密码...", 32, "提示"

        Exit Sub

    End If

    Dim St As String * 2

    Dim s20 As String * 1

    '取得一个0D0A十六进制字串

    Get #1, CMGs - 2, St

    '取得一个20十六制字串

    Get #1, DPBo + 16, s20

    '替换加密部份机码

    For i = CMGs To DPBo Step 2

        Put #1, i, St

    Next

    '加入不配对符号

    If (DPBo - CMGs) Mod 2 <> 0 Then

        Put #1, DPBo + 1, s20

    End If

    MsgBox "文件解密成功......", 32, "提示"

    Close #1

End Sub

第二种：

Option Explicit

    Private Declare Sub MoveMemory Lib "kernel32" Alias "RtlMoveMemory" (Destination As Long, Source As Long, ByVal Length As Long)

    Private Declare Function VirtualProtect Lib "kernel32" (lpAddress As Long, ByVal dwSize As Long, ByVal flNewProtect As Long, lpflOldProtect As Long) As Long

    Private Declare Function GetModuleHandleA Lib "kernel32" (ByVal lpModuleName As String) As Long

    Private Declare Function GetProcAddress Lib "kernel32" (ByVal hModule As Long, ByVal lpProcName As String) As Long

    Private Declare Function DialogBoxParam Lib "user32" Alias "DialogBoxParamA" (ByVal hInstance As Long, ByVal pTemplateName As Long, ByVal hWndParent As Long, ByVal lpDialogFunc As Long, ByVal dwInitParam As Long) As Integer

    Dim HookBytes(0 To 5) As Byte

    Dim OriginBytes(0 To 5) As Byte

    Dim pFunc As Long

    Dim Flag As Boolean

Private Function GetPtr(ByVal Value As Long) As Long

    GetPtr = Value

End Function

Public Sub RecoverBytes()

    If Flag Then MoveMemory ByVal pFunc, ByVal VarPtr(OriginBytes(0)), 6

End Sub

Public Function Hook() As Boolean

    Dim TmpBytes(0 To 5) As Byte

    Dim p As Long

    Dim OriginProtect As Long

    Hook = False

    pFunc = GetProcAddress(GetModuleHandleA("user32.dll"), "DialogBoxParamA")

    If VirtualProtect(ByVal pFunc, 6, &H40, OriginProtect) <> 0 Then

        MoveMemory ByVal VarPtr(TmpBytes(0)), ByVal pFunc, 6

        If TmpBytes(0) <> &H68 Then

            MoveMemory ByVal VarPtr(OriginBytes(0)), ByVal pFunc, 6

            p = GetPtr(AddressOf MyDialogBoxParam)

            HookBytes(0) = &H68

            MoveMemory ByVal VarPtr(HookBytes(1)), ByVal VarPtr(p), 4

            HookBytes(5) = &HC3

            MoveMemory ByVal pFunc, ByVal VarPtr(HookBytes(0)), 6

            Flag = True

            Hook = True

        End If

    End If

End Function

Private Function MyDialogBoxParam(ByVal hInstance As Long, _

ByVal pTemplateName As Long, ByVal hWndParent As Long, _

ByVal lpDialogFunc As Long, ByVal dwInitParam As Long) As Integer

    If pTemplateName = 4070 Then

        MyDialogBoxParam = 1

    Else

        RecoverBytes

        MyDialogBoxParam = DialogBoxParam(hInstance, pTemplateName, hWndParent, lpDialogFunc, dwInitParam)

        Hook

    End If

End Function

Sub Crack()

    If Hook Then MsgBox "破解成功"

End Sub

本文来自博客园，作者：张翰博，转载请注明原文链接：https://www.cnblogs.com/vbashuo/p/15638693.html

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原文链接：https://www.cnblogs.com/vbashuo/p/15638693.html