12-15 11:30 阅读 141

Pygame实战之检测按键正确的小游戏

这篇文章主要为大家介绍了利用Pygame模块实现的检测按键正确的小游戏：每个字母有10秒的按键时间，如果按对，则随机产生新的字符，一共60s,如果时间到了，则游戏结束。快来跟随小编一起学习一下吧

游戏功能

游戏开始，屏幕随机显示一个字符，按 Enter 游戏开始，每个字母有10秒的按键时间，如果按对，则随机产生新的字符，一共60s,如果时间到了，则游戏结束。

import sys, random, time, pygame

from pygame.locals import *

pygame.init()

screen = pygame.display.set_mode((600, 500))

pygame.display.set_caption("打字速度")

while True:

    for event in pygame.event.get():

        if event.type == QUIT:

            pygame.quit()

            sys.exit()

    screen.fill((255, 192, 128))

    pygame.display.update()

首先设置两种字体，然后封装一个屏幕上写字的函数，写出提示。

white = 255, 255, 255

font1 = pygame.font.SysFont("方正粗黑宋简体", 24)

font2 = pygame.font.SysFont("方正粗黑宋简体", 200)

def print_text(font, x, y, text, color=white):

    img_text = font.render(text, True, color)

    screen.blit(img_text, (x, y))

while True:

---

    print_text(font1, 0, 0, "看看你的速度有多快")

    print_text(font1, 0, 30, "请在10秒内尝试")

---

使用 ASCII 字符表，键盘上默认输入的是小写，97 - 122，然后我们使用chr() 函数减去32，就可以得到对应的大写字母，将其写在窗口上

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# 随机的字母

correct_answer = random.randint(97, 122)

while True:

---

    print_text(font2, 0, 240, chr(correct_answer - 32), (255, 255, 0))

---

# 是否按键

key_flag = False

# 游戏是否开始 默认是结束的

game_over = True

# 随机的字母

correct_answer = random.randint(97, 122)

# 分数

score = 0

# 开始时间

clock_start = 0

# 读秒倒计时

seconds = 11

根据用户的按键改变对应的属性，如果游戏重新开始，重置对应的属性。

while True:

    for event in pygame.event.get():

        if event.type == QUIT:

            pygame.quit()

            sys.exit()

        elif event.type == KEYDOWN:

            key_flag = True

        elif event.type == KEYUP:

            key_flag = False

    keys = pygame.key.get_pressed()

    if keys[K_ESCAPE]:

        sys.exit()

    if keys[K_RETURN]:

        if game_over:

            game_over = False

            score = 0

            clock_start = time.perf_counter()

            seconds = 11

使用 time.perf_counter() 获取程序运行到当前的时间，计算差值，实现在屏幕上的倒计时,并根据时间结束游戏或者重新开始

current = time.perf_counter() - clock_start

if seconds - current < 0:

    game_over = True

elif current <= 10:

    if keys[correct_answer]:

        correct_answer = random.randint(97, 122)

        score += 1

        clock_start = time.perf_counter()

if not game_over:

    print_text(font1, 0, 80, "Time: " + str(int(seconds - current)))

    print_text(font1, 500, 40,  str(int(time.perf_counter())))

import sys, random, time, pygame

from pygame.locals import *

pygame.init()

screen = pygame.display.set_mode((600, 500))

pygame.display.set_caption("打字速度")

font1 = pygame.font.SysFont("方正粗黑宋简体", 24)

font2 = pygame.font.SysFont("方正粗黑宋简体", 200)

white = 255, 255, 255

yellow = 255, 255, 0

# 是否按键

key_flag = False

# 游戏是否开始 默认是结束的

game_over = True

# 随机的字母

correct_answer = random.randint(97, 122)

# 分数

score = 0

# 开始时间

clock_start = 0

# 读秒倒计时

seconds = 11

def print_text(font, x, y, text, color=white):

    img_text = font.render(text, True, color)

    screen.blit(img_text, (x, y))

while True:

    for event in pygame.event.get():

        if event.type == QUIT:

            pygame.quit()

            sys.exit()

        elif event.type == KEYDOWN:

            key_flag = True

        elif event.type == KEYUP:

            key_flag = False

    keys = pygame.key.get_pressed()

    if keys[K_ESCAPE]:

        sys.exit()

    if keys[K_RETURN]:

        if game_over:

            game_over = False

            score = 0

            clock_start = time.perf_counter()

            seconds = 11

    screen.fill((0, 100, 0))

    current = time.perf_counter() - clock_start

    print_text(font1, 0, 0, "看看你的速度有多快")

    print_text(font1, 0, 30, "请在10秒内尝试")

    if seconds - current < 0:

        game_over = True

    elif current <= 10:

        if keys[correct_answer]:

            correct_answer = random.randint(97, 122)

            score += 1

            clock_start = time.perf_counter()

    # 如果按键了

    if key_flag:

        print_text(font1, 500, 0, "按键了")

    if not game_over:

        print_text(font1, 0, 80, "Time: " + str(int(seconds - current)))

        print_text(font1, 500, 40,  str(int(time.perf_counter())))

    print_text(font1, 0, 100, "分数: " + str(score))

    if game_over:

        print_text(font1, 0, 160, "请按enter开始游戏...")

    print_text(font2, 0, 240, chr(correct_answer - 32), yellow)

    pygame.display.update()<font face="Arial, Verdana, sans-serif"><span style="white-space: normal;"> </span></font>

以上就是Pygame实战之检测按键正确的小游戏的详细内容

原文链接：https://blog.csdn.net/qq_40801987/article/details/121930906