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Hive基础知识之顾客访问店铺数据分析(UV、Top3)

已知顾客访问店铺的访问日志

user_id shop
u1 a
u2 b
u1 b
u1 a
u3 c
u4 b
u1 a
u2 c
u5 b
u4 b
u6 c
u2 c
u1 b
u2 a
u2 a
u3 a
u5 a
u5 a
u5 a

建表、导表

create table visit(user_id string,shop string) row format delimited fields terminated by ‘\t‘;
load data local inpath ‘/data/visit.dat‘ into table visit;

求每个店铺的UV(访客数)

select shop , count(distinct user_id) as uv from visit group by shop;
shop UV
shop uv
a 4
b 4
c 3

求每个店铺访问次数top3的访客信息。输出店铺名称、访客id、访问次数

1.先求出每个店铺,每个访客的访问次数

select 
	shop, user_id, count(*) as ct 
from 
	visit 
group by 
	shop, user_id;
shop user_id ct
a u1 3
b u1 2
a u2 2
b u2 1
c u2 2
a u3 1
c u3 1
b u4 2
a u5 3
b u5 1
c u6 1

2.计算每个店铺被用户访问次数排名

select 
	shop,user_id,ct,rank() over(partition by shop order by ct) rk
from 
(
	select 
		shop, user_id, count(*) as ct 
	from 
		visit 
	group by 
		shop, user_id
) as t1;
shop user_id ct rk
a u3 1 1
a u2 2 2
a u5 3 3
a u1 3 3
b u5 1 1
b u2 1 1
b u4 2 3
b u1 2 3
c u6 1 1
c u3 1 1
c u2 2 3

3.取每个店铺的前三名

select 
	shop, user_id, ct 
from
(
	select 
		shop,user_id,ct,rank() over(partition by shop order by ct) rk
	from 
	(
		select 
			shop, user_id, count(*) as ct 
		from 
			visit 
		group by 
			shop, user_id
	) as t1
) as t2 
where rk <= 3;
shop user_id ct
a u3 1
a u2 2
a u1 3
a u5 3
b u2 1
b u5 1
b u1 2
b u4 2
c u3 1
c u6 1
c u2 2

The End

原文:https://www.cnblogs.com/ya-ong/p/15308282.html

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代码人生
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