Ajax

用户名和密码实现自检

1、添加jQuery支持

在Web下创建statics包，在statics包下创建js包，导入jQuery.js

2、配置applicationContext.xml文件

3、controller层

public class AjaxController {
    /**
    @RequestMapping("/t1")
    public String test() {
        return "hello";
    }

    @RequestMapping("/a1")
    public void a1(String name, HttpServletResponse httpServletResponse) {
        System.out.println(name);
        if ("baidu".equals(name)) {
            System.out.println("true");
        } else {
            System.out.println("false");
        }
    }

    @RequestMapping("/a2")
    public List a2() {
        List userList = new ArrayList();
        userList.add(new User("java", 1, "male"));
        userList.add(new User("css", 2, "male"));
        userList.add(new User("js", 3, "female"));
        return userList;
    }
**/
    @RequestMapping("/a3")
    public String a3(String name, String pwd) {
        String msg = "";
        if (name != null) {
            if ("admin".equals(name)) {
                msg = "ok";
            } else {
                msg = "error";
            }
        }
        if (pwd != null) {
            if ("123456".equals(pwd)) {
                msg = "ok";
            } else {
                msg = "error";
            }
        }
        return msg;
    }
}

4、前端页面

<%@ page contentType="text/html;charset=UTF-8" language="java" %>


    
    
    



    用户名：
    


    密码：
    

原文：https://www.cnblogs.com/rongchengbanxia/p/14919880.html